Output from php database?

Question

PHP

Good day, there is a problem, there is a mysql database in it 24 fields, 21 of them are of type int and contain either 0 or 1, how to check when outputting, if the value is 0 then the field in the html table is empty, if 1 .. There is an option to check each column, maybe someone will suggest a more adequate solution? I am attaching the code.

<?
          $sql = mysql_query("SELECT * FROM structure");
          while ( $show = mysql_fetch_array($sql)) {
          echo '<tr>';
          echo '<td> <a href="http://'.$show['Link'].'">'.$show['Name'].'</a></td>';
          echo '<td> <p>'.$show['cover_rf'].''.$show['cover_rf'].''.$show['cover_regions'].''.$show['cover_ino'].''.$show['cover_msk'].'</p></td>';
          echo '<td> <p>'.$show['aud_kids'].''.$show['aud_young'].''.$show['aud_buis'].''.$show['aud_par'].''.$show['aud_teach'].'</p></td>';
          echo '<td> <p>'.$show['direct_educ'].''.$show['direct_prof'].''.$show['direct_carer'].''.$show['direct_psy'].''.$show['direct_buis'].''.$show['direct_soc'].'</p></td>';
          echo '<td> <p>'.$show['prof_info'].''.$show['prof_art'].''.$show['prof_games'].''.$show['prof_diagnostics'].''.$show['prof_teaching'].'</p></td>';
          echo '</tr>';
          }

        ?>

Answer 1

$show = array_map(function($v){
 if ($v == 0) return "";
 return "lala";
}, $show);

Answer 2

mysql_list_fields()