Answer the question
In order to leave comments, you need to log in
Answer the question
In order to leave comments, you need to log in
If anyone else needs an answer...
Source string:
Find (with regular expression):
Replace with:
Result:
PS In this case, insert the result of the second regular expression "(.*?)" into the text, for this we enter "\2 "in replacement.
"(.*?)" is any text.
<param name="random">RANDOMTEXT</param>
<param(.*?)>(.*?)</param>
<tag>\2</tag>
<tag>RANDOMTEXT</tag>
<param name="random">
this is a regular replacement type<param(.*?)>
Didn't find what you were looking for?
Ask your questionAsk a Question
731 491 924 answers to any question