Need an integer data type of 8 bytes and 3 bytes C++, how to do it?

Question

linux

I need an integer (preferably another unsigned type) data type of 8 and 3 bytes C++, how to do it? Without using classes. To be cross-platform Windows / Linux.

Answer 1

Use cstdint . 3-byte type does not exist, use 4-byte type.

#include <cstdint>

int64_t foo; uint64_t bar; // 8 байт. Знаковый и беззнаковый.
int32_t foo; uint32_t bar; // 4 байта. Знаковый и беззнаковый.

Answer 2

x64 processors at the instruction level operate with data types of 1, 2, 4, 8 bytes for 3 bytes, you will have to trick your bike, you can do it without and without classes, but with pointers and your own functions.