MongoDB/Mongoose how to remove property from returned object?

Question

MongoDB

I'm doing an update UserModel.findOneAndUpdate(_id, data). The whole object with new data is returned back.
How to say base. so that it does not include a certain property of the object?
For example, here I can control it:
UserModel.findOne({_id}, {property: 0})
Can I do the same here?

Answer 1

you can pass an object with fields that you need or don't need further to the select method

UserModel.findOneAndUpdate(_id, data)
    .select({property: 0})

if you work through callbacks, then you call the exec method, which accepts it

UserModel.findOneAndUpdate(_id, data)
    .select({property: 0})
    .exec(function(err, user) {
        //...
    });

and if through promises - just call then

UserModel.findOneAndUpdate(_id, data)
    .select({property: 0})
    .then(user => {
        //...
    })
    .catch(err => {
        //...
    });