Line by line following links from a list through a for loop?

Question

Python

Hi, I can't figure out how to implement this.
In my "spis" list, links to sites are loaded line by line.
Next, you need to execute the "Brouser,get()" action on each link from the list.
But I can't figure out how to do this, because I create the "get" variable before the loop and I can't add the list to it.
Thank you in advance.

from selenium import webdriver
from selenium.webdriver import Firefox

browser = webdriver.Firefox()

spis = []
with open('file.txt') as f:
    spis = f.read().splitlines()

get = browser.get(spis)



for get in xrange(1,10):
  pass

Answer 1

I think you're over complicating things...

from selenium import webdriver
from selenium.webdriver import Firefox

browser = webdriver.Firefox()

with open('file.txt') as f:
    browser.get(f.readline())