Java. Why doesn't IllegalArgumentException require throws?

Question

Java

Why doesn't IllegalArgumentException require throws?

void some() {
    throw new IllegalArgumentException();    // тут всё нормально, throws не нужен
  }
void some2() {
    throw new Exception();                   // тут ошибка, необходимо try/catch либо throws
  }

Answer 1

Read about what checked exceptions and unchecked exceptions are.

Answer 2

Because IllegalArgumentException extends RuntimeException.
Ah, RuntimeException is UNCHECKED. That's why you don't need try/catch.
In general, you should read about checked / unchecked.
At least here .