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Is it really possible to eat only at the expense of solar panels all year round?
Greetings!
There is no opportunity to be powered by a cable, and according to promises it will appear no earlier than in 2-5 years: D
According to calculations, 20 kW should be enough, I went to a local company, they told a lot of interesting things,
but did not give contacts of more than one real client who could watch live, which led to some doubts.
Would love to hear feedback from real users.
In winter, the constant consumption will be about 10 kW (heating) will only solar panels be enough?
Territorially Leningrad region.
PS offer 150 batteries is not necessary =)
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20 kW is enough for what?
100 sq. m a full-fledged house is about 10 kW per day of electricity and 50-70 kW of heating.
All one needs to store energy, so no matter how without batteries. Another thing is that batteries are needed for lighting and electrical appliances. It is necessary to count on 2-3 days of consumption, taking into account that 12V 100A \u003d 1kW i.e. need 20-30 batteries. You also need a pair of 2kW inverters (preferably 5kW). Heating is done with water, a large boiler of 3-5 cubic meters (preferably more) is heated by the excess energy received from it, the heat is used for heating.
Solar panels in the Leningrad region is a dubious business. Even the coolest panels, even on a very bright day, are more than 0.2 kW per sq. m will not be given for your 20 kW, you will need about 70 square meters. m panels.
Perhaps you should consider the option with a wind generator.
You are confusing the person. Who counts the heating power by squares, not taking into account insulation, glazing, perimeter? And if the house is 2 meters wide and 8 meters long? The area is the same as with 4 * 4, but the perimeter is larger, the area of \u200b\u200bthe walls is larger, the heat loss is higher.
So, the data: Novosibirsk. House 12*14, one floor. Insulation - 250 mm mineral wool. Height from floor to ceiling 2.8. Overlappings are also 250 mm.
Heating with electric converters, 3 * 2 + 2 * 1.5 + 1 * 1 = 10 kW. Everything! Moreover, their maximum capacity is used for less than 30% of the duration of winter.
What if you use a heat pump?
But the main idea: good insulation is cheaper than arrays of batteries.
In alternative energy without batteries - nothing. I am now assembling converters to control this very energy, charge the battery and transfer it to the load, but I also have a power of 2-3 kW in the future from a windmill + SB
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