Is it possible to upload an image and use it without reloading the page?

Question

Django

Is it possible to upload an image and continue working on it without reloading the page?
views.py:

def uploadImage(request):
  if request.method == 'POST':		
    uploaded_file = request.FILES['photo']		
    print(uploaded_file.name)
    print(str(uploaded_file.size) + ' bytes')
  return HttpResponse('test')#пробовал убрать, но получаю ошибку - "ValueError at /upload/"

URLs.py:

url(r'upload/', app.views.uploadImage, name='uploadImage'),

upload form:

<form method="post" id="loadImageForm" name="loadImageForm" enctype="multipart/form-data" action="{%url 'uploadImage'%}">
    {% csrf_token %}
    <input type='file' id="file" name='photo' accept="image/jpeg,image/png"/>
  </form>

Answer 1

Implemented it like this in
index.js:

$(document).ready(function () {
    $('#file').change(function () {
        //var formdata = new FormData($('#loadImageForm')[0]);
        var fileInput = document.getElementById('file');
        var file = fileInput.files[0];
        var formData = new FormData();
        formData.append('photo', file);
        if (formData) {
            $.ajax({                
                url: "uploadImage",
                type: "POST",
                data: formData,
                headers: { "X-CSRFToken": getCookie("csrftoken") },
                processData: false,
                contentType: false,
                success: function () {
                    console.log('success');
                },
                error: function (error) {
                    console.log(error);
                }
            });
        }
    });

    function getCookie(c_name) {
        if (document.cookie.length > 0) {
            c_start = document.cookie.indexOf(c_name + "=");
            if (c_start != -1) {
                c_start = c_start + c_name.length + 1;
                c_end = document.cookie.indexOf(";", c_start);
                if (c_end == -1) c_end = document.cookie.length;
                return unescape(document.cookie.substring(c_start, c_end));
            }
        }
        return "";
    }
});

views.py:

def uploadImage(request):
  if request.method == 'POST':		
    form = forms.FileUploadForm(data=request.POST, files=request.FILES)
    if form.is_valid():	
      print('Done')
    else:
      print(form.errors)
  return HttpResponse('test')

Thanks to alternativshik and Sergey Gornostaev