Is it possible to somehow emit the execution of the php file recorded in the url through routes?

Question

Laravel

This is the request sent
by lara-1c.local/bitrix/admin/1c_exchange.php from 1c and it doesn't matter where else.

How would I make it with routes so that this url is treated as a route and if this request comes in to run the controller function? I can't implement it anyway.

If I simply create the 1c_exchange.php file in the public folder, then this file can even be launched. but I don't need it.
I need to catch all the parameters that are passed along with the file in the controller function.

Answer 1

Laravel doesn't care what you write in its routes. Such a route will be processed in the same way as all the others.

Route::get('/bitrix/admin/1c_exchange.php', function () {
    dd(request()->all());
});

You need to change the Nginx config, most likely you have the following location in it

location ~ \.php$ {
        try_files $uri =404;
        fastcgi_split_path_info ^(.+\.php)(/.+)$;
        fastcgi_pass app:9000;
        fastcgi_index index.php;
        include fastcgi_params;
        fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
        fastcgi_param PATH_INFO $fastcgi_path_info;
    }

He gives you 404
This is what Google gives for this

Answer 2

Route::get('/bitrix/admin/1c_exchange.php', [SomeController::class, 'someMethod'])

?

Answer 3

You need to use a mask so that the framework does not break the route by slashes. Well, do not forget about security, so that absolutely any file cannot be opened.

Route::get('{path}', function ($path) {
    require $path; 
})->where('path, '.*'); // маска