Inheritance of private fields and methods?

Question

Java

Hello, I have a question: there is a class A, it has a private int a; and constructor

public class A{ //open
private int a;
public A(int a){ this.a = a;}

and method

public int pow() { return a*a; }
} //close

.
There is a child class:

public class B extends A{
public B(int a){
super(a); }

At the entry point, more precisely in the main method

psvm(String []args){
A a = new A(5);
B b = new B(6);
int aPow = a.pow();
int bPow = b.pow();
sout("aPow = " + aPow + " bPow = " + bPow);
}

Class "B" does not have a field "a" and I read that private fields are not inherited, how can you explain this?

psvm

means public static void main

Answer 1

Class "B" does not have a field "a" and I read that private fields are not inherited, how can you explain this?

This means that B seems to have such a field, but due to the fact that it is private, only parent methods have access to it.
Class B in your case passes a value to the parent's constructor to initialize that field.

Answer 2

A subclass does not inherit the private members of its parent class. However, if the superclass has public or protected methods to access its private fields, these can also be used by the subclass. Also, if the child class is a nested class of the parent class, then it has access to all private fields and methods of the parent class. In your case, you must call the constructor of the parent class in the child class. This does not mean that you have access to a private field of the parent class.