How to write the name of the same file into a text file?

Question

Python

Good afternoon.
Recently, they transferred me the work of loading registers from banks into 1C. And there was a problem with one bank. a lot of registries come in txt format, and moreover, in one day there may be several of them the same, for example, with this name (40104161) 6 files, since the mail program, when saving all files, can add a counter to the repeated file names and as a result I get this such a set of files (40104161; 40104161(1); 40104161(2); 40104161(3), etc.). in the file itself, the first line contains the file name, but for those to which the counter is added to the bracket, it does not match and 1C does not accept it, so you have to manually open each file and rewrite the first line.
The question is how to write a script that would read the filename and overwrite the first line in the file itself?

Answer 1

Hold on. Create a file with this code, put it in your files folder and enjoy (well, or tweak the path with the code)

for f in listdir('.'):
    if not f.endswith('.py'):
        replace = f
        source = f.split('(')[0]
            
        file = open(f, 'r')
        text = file.read()
        file.close()

        file = open(f, 'w')
        file.write(text.replace(source, replace))
        file.close

Answer 2

Batnik can be easily implemented.
Here is a code sketch:

for %%a in (c:\temp\*) do (
 echo.%%~nxa - Это имя файла
 echo.Следующая команда выводит текстовый файл на экран, пропуская первую строку.
 for /f "usebackq tokens=* skip=1 delims=" %%b in ("%%~a") do echo.%%b
)

The idea must be clear. Then you will bring yourself to mind.

Answer 3

The only way to do something like this with a text file is to write to a temporary file, then replace the old one with this temporary one. So it will be something like (I write in pseudo-C ++)

открыть исходный и временный файлы
if (std::getline(исходный, s)) {
  подкорректировать s
  временный << s << std::endl;
  while (std::getline(исходный, s) {
     временный << s << std::endl;
  }
  закрыть оба файла
  уничтожить исходный
  переименовать временный
}

The main problem is Unicode filenames, which I hope you don't have.
And, of course, do not forget about the byte order mark, if the files have it.

Answer 4

You would replace the brackets with underlining 40104161(1) -> 40104161_1.
And then he rewrote the first line of the file, copying his name into it.
To do this, you need two scripts (in python, shell or whatever): the first script replaces this bracketed suffix of the file transferred to it with an underlined suffix; the second script simply takes the file and writes its name on its first line.
And above them is the third script, which runs the first script for the file, and then the second one.
And when you have this third script, you run it in a loop for a list of files.