How to write in url.py correctly?

Question

Django

There are two functions. Both have a slug field, how do I get them both processed in url.py? Such an option as I have now processes only the top line. I understand why this happens, but here's how to make both functions work. They need to be without url like arenda/(?P[-\w]+)/$/.

url(r'^(?P<slug>[-\w]+)/$', Arenda.as_view()),
url(r'^(?P<slug>[-\w]+)/$', Sale.as_view()),

Answer 1

Hang on different urls.

url(r'^rent/(?P<slug>[-\w]+)/$', Arenda.as_view()),
url(r'^sale/(?P<slug>[-\w]+)/$', Sale.as_view()),

Answer 2

does not
work until the first find. no further processing
if you want to merge two views - merge at the template level with context passing