How to work with bytes during shift operations?

Question

Java

There is a series of numbers with type byte
32 0x20
64 0x40
96 0x60 -128
0x80
-96 0xA0
-64 0xC0
-32 0xE0 byte b1 = (byte) 32; b1 >>> 5; with positive numbers all the way, we get 1,2,3 but then garbage: byte 134217724, 134217725, 134217726, 134217727. Did I understand correctly that a virtuoso machine first converts these values ​​to 4 bytes and only then shifts them. How to make it move right away? those. 0xA0 (1010 000) to 0x05 (0000 0101)? PS (b1 & 0x00FF) >>> 5) I don't want to. I want with a byte.

Answer 1

JLS 15.19. Shift Operators
Unary numeric promotion (§5.6.1) is performed on each operand separately.
JLS 5.6.1. Unary Numeric Promotion
Otherwise, if the operand is of compile-time type byte, short, or char, it is promoted to a value of type int by a widening primitive conversion (§5.1.2).
Those. Yes. First, all bytes are converted to ints and it won't work without a mask.