How to work with a function with a large number of optional parameters?

Question

Python

I have a function with a lot of optional parameters
example

def fun(name="name", time=0, size=300, color="#fff"):

And in order to change the color parameter, I need to write . Is it possible to shorten this somehow? the only thing I came up with is to use an associative array
fun("name", 0, 300, "#ff0"):

def fun(arr):
  name =  ["name", "time", "size," "color"]
  val = ["name", 0 , 300 , "#fff" ]
  num = 0
  for key in name :
    try: 
      arr[key]
    except KeyError:
      arr[key] = val [num ]

Arr = {
"color"="#ff0"
}
fun(Arr)

But is there a better way to do this?

Answer 1

def fun(**kwargs):
    color = kwargs.get('color')

PS well and

def fun(name="name", time=0, size=300, color="#fff"):

simple enough
fun(color="#ff0")