How to use variable as class name in LESS mixin?

Question

Less

Caution, terrible wrong syntax.
How can you write such a mixin?

.social(@social, @color){
  .color_[email protected]social{
    color: @color;
  }
}

What would with such a call

.social('facebook', '#ff0000');
.social('vkontakte', '#00ff00');

was this the result?

.color_facebook{
  color: #ff0000;
}
.color_vkontakte{
  color: #00ff00;
}

I understand that LESS is not ok right now, but please don't suggest anything else. We need to resolve this issue on LESS.
Thank you.

Answer 1

So?

.social(@social, @color){
  [email protected]{social} {
    color: @color;
  }
}

.social(facebook, #ff0000);
.social(vkontakte, #00ff00);

preview