How to use the "!" in iptables?

Question

iptables

man iptables says the following:
A "!" argument before the address specification inverts the sense of the "parameter".
But when I try to write below rule -
iptables -A INPUT -p tcp -s ! 192.168.1.60 --dport 22 -j DROP
when I run the rules, I get the following error -
Bad argument `192.168.1.60'
Could you give me an example or point out where to write the "!" argument so that it is executed?

Answer 1

First, "-s ! 192.168.1.60" is stuck in the middle of another construct, don't do it like that.
Correct:
iptables -A INPUT ! -s 192.168.1.60 -p tcp --dport 22 -j DROP
Note that "!" before "-s", not after (it used to be possible, but now it's not).