How to unpack dictionaries in a list in Django?

Question

Django

Hello everyone!)
Help solve the problem.
The following data structure is passed to the template context:

context = [{key:value, key:value},{key:value, key:value,},{key:value,key:value,},{key:value,key:value,}]

This is how I tried to extract key values ​​from a dictionary.

{% for menu_dict in menu_dict_list %}
        <tr>
                {% for key,value in menu_dict%}
                        <td>{{value}}</td>
                {% endfor %}
        </tr>
{% endfor %}

As a result, I wanted to get this picture:
the first dictionary ----
+ the value of the first key
+ the value of the second key
========================
the second dictionary- ----
+ value of the first key
+ value of the second key
=======================...... and so each dictionary in the list
In the template with the help of {% for in context %}
I tried to pull out the values ​​of the keys in different ways, but nothing came of it (
Either returns None.
Or iterates the key itself without values.
Help with fresh ideas.

Answer 1

Would you show the exact code of the view, otherwise your context is equal to the list, and in the template you are already working with some kind of menu_dict_list. But suppose you have something like:

def some_view(request):
    ctx = {
        'menu_dict_list': [{'key11': 1, 'key12': 2}, {'key21': 3, 'key22': 4}, {'key31': 5, 'key32': 6}]
    }
    return render(request, 'some_template.html', ctx)

then you can get around it in the template like this:

{% for d in menu_dict_list %}
    {% for k, v in d.items %}
        {{ k }} - {{ v }}<br>
    {% endfor %}
{% endfor %}