How to turn regexp into 1 line?

Question

go

I have a string:

КАТЕГОРИЯ: ТекстИСТЕЦ: Текст.ОТВЕТЧИК: Текст

I extract "Text" from it:

re := regexp.MustCompile(`(КАТЕГОРИЯ:\s+)(.*)(ИСТЕЦ)`)
re := regexp.MustCompile(`(ИСТЕЦ:\s+)(.*)(ОТВЕТЧИК)`)
re := regexp.MustCompile(`(ОТВЕТЧИК:\s+)(.*)`)

how to make regular expressions like this from the data:

re := regexp.MustCompile(`(?P<Year>\d{4})-(?P<Month>\d{2})-(?P<Day>\d{2})`)
re := r.FindStringSubmatch(`2015-05-27`)

Without calling 3 times:

re := regexp.MustCompile(``)

Answer 1

КАТЕГОРИЯ:\s+(?P<Category>.*)ИСТЕЦ:\s+(?P<Plaintiff>.*)ОТВЕТЧИК:\s+(?P<Defendant>.*)

https://regex101.com/r/YOLDZl/2