How to split a string into an array of strings with a specific length?

Question

Swift

Task: There is a string with an arbitrary length, consisting of numbers. It is

necessary to divide this string into an array of substrings, indicating the length of these substrings
"123456789" (the length of the substring is 4) -> ["1234", "5678", "9"]

I came up with this solution:

var str = "123456789"
let sz = 4
for chunk in stride(from: sz, to: str.count, by: sz).reversed() {
    str.insert(" ", at: str.index(str.startIndex, offsetBy: chunk))
}
let chunksOfString = str.components(separatedBy: " ")

Question: is it possible to somehow break a string into an array of substrings with a certain length in a less barbaric way?

Answer 1

extension String {
    func components(withLength length: Int) -> [String] {
        return stride(from:0, to: self.count, by: length).map {
            let start = self.index(self.startIndex, offsetBy: $0)
            let end = self.index(start, offsetBy: length, limitedBy: self.endIndex) ?? self.endIndex
            return String(self[start ..< end])
        }
    }
}

let str = "123456789"
let comp1 = str.components(withLength: 4)
let comp2 = str.components(withLength: 3)

dump(comp1)
dump(comp2)

Exhaust