How to split a string in ruby ​​on the first occurrence or on a specific word?

Question

ruby

Let's say there is a string "one word and many words in a sentence".

If I do , then the result will be . And you need to get :. That is, split by the first occurrence found in the string. Or split the string exactly by the word word, and if there are more letters in the word, then this is not considered a match. str.split('word')['one ', ' and many ','s in a sentence']

['one ', ' and many words in a sentence']

Answer 1

Using the regular expression \bword\b, where \bmeans a word boundary:
str.split(/\bword\b/)