How to split a number into parts?

Question

C++ / C#

Hello. You need to break the number into unequal parts.

I'd better show you with an example.

There is a number 2000. The number can be negative.
It must be divided into a random number of parts, for example, in the range from 5 to 10. For example, it fell out to be divided into 8 unequal parts. At the output, for example, we get:
203, 242,274,215,301,402,112,159,92

At the output we get an int array.

You can also make an error. That is, in total we get not exactly 2000, but we can get 2100.

Answer 1

I'm afraid to imagine why this might be needed, but since they ask:

int num = 2000;
int parts = 10;
Random rnd = new Random();

List<int> result = new List<int>();

for (int i = 0; i < parts - 1; i++)
{
    int tmp = rnd.Next(0, num / 2);
    if (tmp == 0) { i--; continue; } 
    result.Add(tmp);
    num -= tmp;
}

result.Add(2000 - result.Sum());

result = result.OrderBy(i => Guid.NewGuid()).ToList();

Console.WriteLine(result.Sum());

Answer 2

Well, even if in total you can not get 2000 back, then it’s generally easy.
Divide 2000 by 8 to get the base number. Then we simply add or subtract some random number to this base number.