How to sort the dictionary first by keys, and then by each key a list?

Question

Python

Goodnight. Suppose we have the following dictionary:

{
  'foo': [
    'val2',
    'val1',
    'val3'
  ],
  'bar': [
    'b1'
  ],
  'mem': [
    'ab1c',
    'b1ca'
  ]
}

Final dictionary:

{
  'bar': [
    'b1'
  ],
  'foo': [
    'val1',
    'val2',
    'val3'
  ],
  'mem': [
    'ab1c',
    'b1ca'
  ]
}

I hope I manually sorted the final one correctly. That is, first the keys in alphabetical order, then in each key the list in alphabetical order

Answer 1

a = {
  'foo': [
    'val2',
    'val1',
    'val3'
  ],
  'bar': [
    'b1'
  ],
  'mem': [
    'ab1c',
    'b1ca'
  ]
}


b = dict([(x[0], sorted(x[1])) for x in sorted(a.items())])