How to solve the problem about the solar wind and mass loss?

Question

Physics

Yes, the question (title) is a little strange... and "do it for me" here, it seems, they don't like it, which is generally correct.
Problem formulation: "solar wind protons reach the Earth in 3.5 days, while at 1 cm ^ 3, at a distance of 1 AU from the Sun, there are on average 5 solar wind particles (protons).
What mass does the Sun lose with the solar wind per day?"
UPD: Found a bug. now the solution is more realistic (see the 2nd last paragraph of the question), now I want to know what do you think about it, is it correct or not?
Here is my solution https://gist.github.com/anonymous/a7cb2666dfd1080b1e7a
According to Wikipedia , then
"Due to the solar wind, the Sun loses about one million tons of matter every second. The solar wind consists mainly of electrons, protons and helium nuclei (alpha particles); the nuclei of other elements and non-ionized particles (electrically neutral) are contained in a very small amount."
It is clear that in addition to protons, there are also relatively heavy helium nuclei and other electrons, but still, for some reason it seems to me that my answer is not correct.
Although it is not far from a million tons, it is 10^9 kg, and I have 10^6 kg

Answer 1

That is, in your opinion, a discrepancy of 3 orders of magnitude is "not far"?
I didn’t look at your solution, but just in 5 minutes I got a value of 2,177,442,960 kg / day. This is 2 times more than 1 billion kg ...
I took 1 AU in cm (l) (this is the distance from the Earth to the sun), multiplied by the mass of the proton (m) in kg, multiplied by the area of ​​the sun (s ) in cm, multiplied by the number of protons (n ​​= 5 pcs) and divided by r number of days (t = 3.5).
M=l*m*s*N/t
And don't forget about SI.
If it's not a secret, where do you study/studied?