How to solve json to object problem?

Question

PHP

The problem is that I send data to the server, the server performs some action and sends a response to the client, everything is fine, well, it gets json to the client, well, when trying to convert using $.parseJSON(), it displays an error. And yet, the joke is that everything works fine on the local, but uploaded it to the hosting, the following error appeared:
"
XHR finished loading: POST "..../vote/set_vote". jquery.js:4
{"response_text": "\u0412\u0430\u0448 \u0433\u043e\u043b\u043e\u0441 \u0443\u0441\u043f\u0456\u0448\u043d\u043e \u0434\u043e\u0434\u0430\u048d\u043"statures" :"100"} common.js:129
Uncaught SyntaxError: Unexpected token
"
Client code:

$.post(
            url + "/vote/set_vote",
            {id_answer:id},
            function(data){
                console.log(data);
                var json = JSON.parse(data);
                $('#area_vote').html("<h3 align='center'>"+json.response_text+"</h3>");
                switch(json.response_status){
                    case '100':{
                        $('#area_vote').attr("id","area_answer");
                        setTimeout(build_block_vote(),3000);

                    }
                        break;

                    case '101':{

                    }
                        break;

                }
}

Server script

setcookie("ses_vote","1",0x6FFFFFFF);

            $query = "Запрос";
            $q = mysql_query($query) or die(mysql_error());


            if($q){
                return json_encode(array(
                    "response_text"=>"Все отлично",
                    "response_status"=>"100"
                ));
            }
            else{
                return json_encode(array(
                    "response_text"=>"Случилась ошибка",
                    "response_status"=>"101"
                ));
            }

Answer 1

Quite a valid json. Try it like this

$.post(url + "/vote/set_vote", {id_answer:id})
   .done(function(data) {
        var json = JSON.parse(data);
        console.log(json);
    });

Answer 2

what does console.log(data) show?

Answer 3

Are the server address and the address of the site from which the request is made the same?
If not, then use JSON-P

Answer 4

Most likely, you are trying to parse a finished object. When a request comes from the server, jquery itself parses json, if json data comes from the server

$.post(url + "/vote/set_vote", {id_answer:id}, function(response) {
  console.log(response);
});

See what will be output to the console

Answer 5

You obviously have extra non-printable characters there. Look at the variable in the debugger, maybe it will be more visible.

Answer 6

And what dataType is sent by the server?

Answer 7

Fix encoding issues. The problem of erroneous data parsing is precisely in this.
And the browser also finds errors in the HTML code of the page.