Answer the question
In order to leave comments, you need to log in
How to solve a problem in C++?
Write a program that will determine and display one factor out of N that can be omitted from the product
of 1! x2! x 3! x ... x N! so that the remaining product is an exact square.
PS it is clear that
one! x2! x 3! x4! = 122if you remove 2! then everything is correct, but if N is odd, for example 5,7,9, then what to do?
Answer the question
In order to leave comments, you need to log in
#include<iostream>
using namespace std;
double faktorial(int n)
{
if (n == 0) return 1;
return n*faktorial(n - 1);
}
double isSquare(float n)
{
double k;
if (n == 0) return 0;
k = sqrt(n);
if (k == (int)k) return 1;
else return 0;
}
int main()
{
int n,temp;
double f, s = 1;
bool flug = true;
cin >> n;
for (size_t i = 1; i <= n; i++)
{
s *= faktorial(i);
}
cout << isSquare(s) << endl;
for (size_t i = 0; i < n; i++)
{
temp = n - i;
f = s / temp;
if (isSquare(f))
{
cout << temp << endl;
flug = false;
break;
}
}
if (flug) cout << "Not found "<<endl;
system("pause");
return 0;
}
Where did the task come from? Is there a link to the original? Are there any examples there?
While the impression that the authors wanted something else.
In this case, "help" - decide for you? No thanks, no need...
Didn't find what you were looking for?
Ask your questionAsk a Question
731 491 924 answers to any question