How to simplify code that replaces values ​​in a dictionary?

Question

Python

How can the following code be simplified?

if r['opcode'] == 1:
    r['opcode'] = str(r['opcode']).replace('1', 'Оплата')
if r['opcode'] == 2:
    r['opcode'] = str(r['opcode']).replace('2', 'Возврат')
if r['opcode'] == 3:
    r['opcode'] = str(r['opcode']).replace('3', 'Рекуррентное списание')
if r['opcode'] == 4:
    r['opcode'] = str(r['opcode']).replace('4', 'Блокировка')

Answer 1

d = {
    1: 'Оплата',
    2: 'Возврат',
    3: 'Рекуррентное списание',
    4: 'Блокировка',
}

r['opcode'] = d[r['opcode']]

Answer 2

To change the value in the dictionary, you can simply:
if r['opcode'] == 1:
r['opcode'] = 'Payment'

Answer 3

r['opcode'] = ['Оплата', 'Возврат', 'Рекуррентное списание', 'Блокировка'][r['opcode'] - 1]