How to show the site itself in the view?

Question

Django

Let's say there is a function that returns text with the word "Test":

def index(request):
    return HttpResponse("<h1>Тест</h1>")

Its URL is written like this:

from django.conf.urls import url
from django.contrib import admin
from shop import views

urlpatterns = [
    url(r'^test/', views.index),
]

Now the question is how to return the site view itself in the def index (request) function? I will not push the weight of the site's html into the def index (request) function.

Answer 1

Read for templates

Answer 2

You should not return html code in the view in any way at all.
Judging by the question, I can only recommend reading the documentation further.