How to setup entry point in webapp?

Question

Java

Worth TomCat 9 I write in the latest IntelliJ IDEA wrote a couple of servlets everything works but not as it should! In the web.xml file, I registered a wellcome file

<welcome-file-list>
        <welcome-file>/index.jsp</welcome-file>
    </welcome-file-list>

There is also a servlet in web.xml

<servlet>
        <servlet-name>WarmStar</servlet-name>
        <servlet-class>warmStar.WarmStar</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>WarmStar</servlet-name>
        <url-pattern>/warmStar</url-pattern>
    </servlet-mapping>

When index.jsp is launched, it also works out the url in the browser like this - localhost: 8085 I need the url to be like this at the first start - localhost: 8085 / warmStar so that it would be right away. That is, it turns out that the servlet would immediately start working, which displayed this index.jsp page to me. I tried to change the url pattern to an empty one in the servlet mapping or just put a slash, the servlet executes index.jsp, but the url path in the browser remains like this localhost :8085 In a arc in a servlet I'm doing a forward on index.jsp And yes, it's worth saying that this is my first application, I'm sorry if I wrote nonsense. Thank you.

Answer 1

The web application itself (at least its web part) does nothing at startup.
All the magic starts with an http request.
In order for Idea to open the correct url:
Run/debug configuration->Tomcat Server->Server->Open Browser
-Check After launch
-Set url
Original instructions:
https://www.jetbrains.com/help/idea/run- debug conf...

Answer 2

So who's stopping you from changing /index.jsp to the right path? You mean replace /index.jsp with /warmStar ?