How to set up a redirect in nginx taking into account the existence of a file?

Question

Nginx

Good day!
There is a website sitename.ru There is
such a structure of folders/files relative to $ root :
./test.html
./test2
./test2/index.html
./test2/b.html ./test.html (if there is none, check the next option) =>./test/index.html (if there is, we return it, otherwise...) => 404 sitename.ru/test2 => ./test2.html (if there is no such thing, check the next option) =>./test2/index.html (if there is, we return it, otherwise...) => 404 sitename.ru/test2/b => ./test2/b.html (if there is no such, check the next option) => ./test2/b/index.html (if there is, we give it away, otherwise...) => 404



What is the correct way to write rewrite for such conditions, so that it is unified, without being tied to the name of the directory (there are many files and directories)?

Answer 1

It is correct to write try_files

location / {
    try_files $uri $uri.html $uri/index.html =404;
}

And if I type example.com/test/(with a slash at the end), then what should come out?