How to separate arguments in a line in bash for a strace program?

Question

linux

Example
exePath="path_to_program";
exeArgs="--param1=sdfsdf --param2=sdfdf"
strace -xf -o 'path' "$exePath" "$exeArgs"
The program launched in strace takes only one param1 parameter, with a string value with all parameters.

Answer 1

You have too many quotes

exePath="path_to_program";
exeArgs="--param1=sdfsdf --param2=sdfdf"
strace -xf -o path $exePath $exeArgs

Answer 2

The best solution I know is with an array:

args=("--param1=value1" "--param2=value with spaces")
"$cmd" "${args[@]}"

Each element of the array will be passed as one parameter.