How to send a photo to the site through a form and return a link?

Question

Python

The site has an image upload form, after uploading the image, a download link is displayed (namely, an attribute appears in the form tag):

<form method="GET" id="file_link" action="/output/20200702125307337580.jpg">

I'm trying to upload an image via requests and then get the contents of the action attribute, but I end up with None, what could be wrong? The code itself:

url = 'http://color.photofuneditor.com/ceremony'
        link_img[user_id] = src
        data = {'name': 'file', 'type': 'submit'}
        files = {'file': (link_img[user_id], open(link_img[user_id], 'rb'))}
        req = requests.get(url, data=data, files=files)
        if req.ok:
            bot.send_message(message.chat.id, "Ждем 15с")
            time.sleep(15)
            img = requests.get('http://color.photofuneditor.com/ceremony')
            soup = BeautifulSoup(img.text, "lxml")
            img_p = soup.find('form', {'id': 'file_link'})
            print(img_p.get('action')) #выводит None

Answer 1

It shouldn't show up there.
POST to color.photofuneditor.com/ceremony-vegas
Parameter fileToUpload Parameter
content - base64 images
Response - new file name

import requests
import base64


with open("nums.jpeg", "rb") as image_file:
    image_hash = base64.b64encode(image_file.read()).decode("utf-8")

encoded_image = 'data:image/jpeg;base64,{}'.format(image_hash)
payload = {'fileToUpload': encoded_image}

r = requests.post('http://color.photofuneditor.com/ceremony-vegas', data=payload)

if r.status_code == 200:
    image_url = 'http://color.photofuneditor.com/output/{}'.format(r.json()['file_link'])
    r = requests.get(image_url)

    with open('new_image.jpg', 'wb') as f:
        f.write(r.content)