How to return a message if nothing is found?

Question

MongoDB

I'm running an ExpressJS server. There is a handler:

router.get('/articles/:section', Article.getArticlesBySection)

exports.getArticlesBySection = (req, res, next) => {
  Article.find({section: req.params.section})
    .then((articles) => {
      if (!articles) {
        // FIX THIS
        return res.status(404).json({
          message: 'Articles doesn\'t exist'
        })
      }
      return res.status(200).json(articles)
    })
    .catch((err) => {
      return next(err)
    })
}

I have 3 in total section. I want to return a message to the user if there is a call to a route that doesn't match my section. The problem is that if .findit doesn't find anything, then it doesn't work.

if (!articles) {
        // FIX THIS
        return res.status(404).json({
          message: 'Articles doesn\'t exist'
        })
      }

And it returns an empty array of the form []
How to handle this? Maybe I should use another Mongus method? Because it .findOneworks as intended with a similar code (I use it if the address of a specific note is wrong.

Answer 1

check array length?