How to retry a webrequest on error (C#)?

Question

Parsing

req         = (HttpWebRequest) WebRequest.Create(get_url);
   req.Timeout = 1500;
   resp        = (HttpWebResponse) req.GetResponse();
   sr          = new StreamReader(resp.GetResponseStream(), Encoding.GetEncoding("utf-8"));
   content     = sr.ReadToEnd();
   sr.Close();

How to make a forced request cycle if the response code is not 200?
Sometimes the content is NOT returned by the link (the API is overloaded) - but when the request is repeated, a valid response is returned.

Thanks

Answer 1

1. You just repeat requests in a cycle with some periodicity
2. Instead of WebRequest, it is better to use HttpClient
3. To avoid sawing bicycles - use Polly

Answer 2

while(True){
    try{
      здесь твои запросы
    }
    catch{
       ...
    }
}

Answer 3

Through recursion, as an option

async Task<string> SendRequestUntilSuccess(string url)
{
    try	
    {
        HttpResponseMessage response = await client.GetAsync(url);
        response.EnsureSuccessStatusCode();
        return response.Content.ReadAsStringAsync();
    }
    catch(HttpRequestException e)
    {
        return SendRequestUntilSuccess(url);
    }
}