How to replace with interface?

Question

typescript

there is a function

function test(a: number, b: string, c: () => void): void {
  ...
}

how to use interface here?

interface TestInterface {
  a: number;
  b: string;
  c: () => void;
}

Answer 1

function test({a,b,c}: TestInterface)

Answer 2

Use the Robur variant .
Why? Because in a general sense, what you want to automatically get is impossible, because. the order of the keys in the object (and interface) does not matter, i.e. there is no difference between:

interface TestInterface {
  a: number;
  b: string;
  c: () => void;
}

and

interface TestInterface {
  c: () => void;
  a: number;
  b: string;
}

and in function, obviously, has.
You can do it manually like this:

function test(a: TestInterface['a'], b: TestInterface['b'], c: TestInterface['c']): void {
  // ,,,
}

If the order of the arguments doesn't really matter, you can make a nightmare of a complex type in a prinip using ...args, but you don't have to.)

Answer 3

the common type for all function arguments (aka rest parameter type) is tuple .
so, in your case , you need to pass it with three dots. the only thing is, if you pass the array directly as a literal, you will need to indicate that it understands that this is a tuple. here's an example of what works and what doesn't in the playground .