How to remove a space in a parameter in bash?

Question

linux

People, I can't figure out where the mistake is

first=$(echo $1 | xargs)
alias trunc_spv='echo /var/log/supervisor/$first'

This code does not cut spaces, but if you write instead, spaces will be cut. Specifically, the task is such. It is necessary to make an alias that will execute the command to clean up a file in a specific directory. The directory is static, only the file in that directory is dynamic. But the file comes with a space in front of $1, so the space needs to be cut. How?.. Thank you!
first=$(echo $1 | xargs)
first=$(echo ' p ' | xargs)

Answer 1

first=$(echo "$1" | xargs)- put the shell variable in quotation marks.

Answer 2

man tr
https://linux.die.net/man/1/tr

Answer 3

In short, everything was simple - aliases do not allow parameters to be used (((