How to remake to: input of initial arrays; output of initial arrays; processing arrays; in the output of the result were through functions?

Question

C++ / C#

#define _CRT_SECURE_NO_WARNINGS

#define _CRT_NONSTDC_NO_WARNINGS

#include <stdio.h>

#include <stdlib.h>

#include <locale.h>

int main()

{

setlocale(LC_ALL, "");

int A[5], B[6], C[11];

int* d, * w, * e;

int i, j,tmp;

int k = 0;

d = A;

w = B;

e = C;

srand(time(NULL));

for (i = 0; i < 4; i++)

{

*(d + i) = 10 + rand() % 90;

*(C + k++) = *(d+i);

}

for (i = 0; i < 6; i++)

{

*(w+i) = 10 + rand() % 90;

*(C+k++) = *(w + i);

}

for (i = 0; i < 10 - 1; i++)

{

for (j = 0; j < 10 - i - 1; j++)

{

if (*(e+j) > *(e+j + 1))

{

int tmp = *(e+j);

*(e + j) = *(e+j + 1);

*(e + j + 1) = tmp;

}

}

}

for (i = 0; i < 10; i++)

{

printf("Элемент массива %d \n", *(e + i));

}

return 0;

}

Answer 1

#define _CRT_SECURE_NO_WARNINGS
#include
#include
#include
#include
void vvodA(int* A, int* C)
{
for (int i = 0; i <= 4; i++)
{
A[i] = 10+ rand() % 90 ;
C[i] = A[i];
}
}
void vvodB(int* B, int* C)
{
for (int i = 5; i <= 10; i++)
{
B[i - 5] = 10+ rand() % 90;
C[i] = B[i - 5];
}
}
void sort(int* C)
{
for (int i = 10, j = 0; i >= 0; j--)
{
int end = 1, min = 0;
for (j = 0; j < i; j++)
{
if (C[j] > C[j + 1])
{
min = C[j];
C[j] = C[j + 1];
C[j + 1] = min;
end=0;
}
}
if (end == 1)
break;
}
}
void print(int* C)
{
for (int i = 0; i <= 10; i++)
{
printf("Array element %d: %d \n", i + 1, C[i]);
}
}
int main()
{
setlocale(LC_ALL, "");
int A[5], B[6], C[11];
srand(time(NULL));
vvodA(A, C);
vvodB(B, C);
sort(C);
print(C);
}