How to queue a task to an existing parallel thread in Python 3?

Question

Python

All the best! I'm just learning Python, and now I ran into a problem:
I have a function for working with google tables, in it I read the number of filled rows and enter new data in row_count +1 . But the process of writing to the table takes a long time, and I decided to perform this action in a new thread in order to be able to accept new requests to write to the table. But I get a new thread every time, and I just need to queue up in this separate thread, because the request to get the number of filled rows is fast, it turns out that I write different data to the same row , since row_counteverything is looking for the previous one, because the previous record is only found in the process and has not ended yet

def append_to_sheet(id):
  action_time = datetime.now().strftime("%Y.%m.%d %H:%M:%S")
  row = [action_time, id]
  row_count = len(sheet.get_all_values())
  index = row_count +1
  sheet.insert_row(row, index)


def start_with_thread():
  while True:
    id = q.get()
    append_to_sheet(id)
    q.task_done()

and this is called

t = threading.Thread(target=start_with_thread)
t.setDaemon(True)
t.start()
q.put(id)

each time a request is received to write to the table, and accordingly, each time a new thread is created in which row_count will be the same value if the new request arrived earlier than the previous record to the table ended. Something like this

Answer 1

It is necessary to:
1) create the thread only once, at the start of the program
2) use a Queue to communicate with it: https://docs.python.org/2/library/queue.html
An alternative to be much simpler is to use Celery www.celeryproject.org _