How to put each match from a regular expression into an array?

Question

Java

We parse the page and get matches, we know in advance that there will be 452 matches. it should look like this mass[0] = "first match", mass[1] = "second match". It turned out only to put all one cell [0] = "all matches" =(
Teach me please!

String output = "";
            StringBuffer totalOutput = new StringBuffer();

            while ((output = br.readLine()) != null) {
                Matcher regUrl = Pattern.compile("yes.>([0-9]{9})").matcher(output);


                while (regUrl.find()) {
                    System.out.print(regUrl.group(1) + " ");
                }

                Matcher regUrl1 = Pattern.compile("blank.>([0-9]+)").matcher(output);

                while (regUrl1.find()) {
                    System.out.println(regUrl1.group(1));
                }
            }

Answer 1

String line = "This order was placed for QT3000! OK?";
      String pattern = "(.*)(\\d+)(.*)";

      // Create a Pattern object
      Pattern r = Pattern.compile(pattern);

      // Now create matcher object.
      Matcher m = r.matcher(line);
      if (m.find( )) {
         System.out.println("Found value: " + m.group(0) );
         System.out.println("Found value: " + m.group(1) );
         System.out.println("Found value: " + m.group(2) );
      } else {
         System.out.println("NO MATCH");
      }

Take an example. It's not hard to understand :)