How to pull the file with the maximum number?

Question

Python

Task: there is a folder with text data .txt, where all the names are ordered like: "1.txt", "2.txt", "3.txt" .... "15.txt", "16.txt" and so on .d. How to take a file with the last (maximum) number and create a file with the next number and work with it already. For example, if the maximum is "25.txt", then you need to create "26.txt" and work with it already. How to implement this in Python with open()

Answer 1

from pathlib import Path

max_id = max(int(path.stem) for path in Path('path_to_folder').glob('*.txt'))