How to process the result of a command through grep?

Question

linux

Good day
Tell me how to process the result of the command

#/bin/bash
error = $(sudoedit -s / | grep ...не знаю как написать что бы результат вывел   ;/  )
error2 = ;/
if error == error2 
then
........

sudoedit -s / -opens the editor, maybe it's worth checking if it opens or not? I don't understand how to do it

Answer 1

sudo -V | head -n 1 |awk '{ print $3 }'
conclusion

1.8.21p2

Now check the version

if [ "$(sudo -V | head -n 1 |awk '{ print $3 }')" = "1.8.21p2" ]; then
echo "все сработало"
fi

We complicate, as I understand it, you need to exclude certain versions, for this you will need to either make several if or elsif

if ; then 
  echo "все сработало 1.8.21p2"

elif ; then 
 echo "все сработало 1.0"

fi

If you clearly understand what you want, then you can do it in 1 line ,
for example
. If not this, and not this, then
describe what you want, for example, if this is a version above a certain one, then there may be problems because there are already letters inside