How to pass variable to base template?

Question

Django

There are many pages on the site, they all inherit from one base.
It is necessary to pass the variable to the base template so that these variables are not written for each page.
According to the Django documentation, this can be done using the RequestContext.
This code from the documentation works great

from django.http import HttpResponse
from django.template import RequestContext, Template

def ip_address_processor(request):
    return {'ip_address': request.META['REMOTE_ADDR']}

def client_ip_view(request):
    template = Template('{{ title }}: {{ ip_address }}')
    context = RequestContext(request, {
        'title': 'Your IP Address',
    })
    return HttpResponse(template.render(context))

Problem starts when trying to include html file

def home(request):
    template = get_template('home/home.html')
    context = RequestContext(request, {
        'title': 'Your IP Address',
    })
    return HttpResponse(template.render(context))

An error is thrown: TypeError: context must be a dict rather than RequestContext.
Please help. Thank you very much in advance.
Answer: RequestContext is not needed at all. You need to register a context processor, specify it in settings.

def custom_proc(request):
    "A context processor that provides 'app', 'user' and 'ip_address'."
    param = request.session.get('Param')
    data = {"param":param}
    return data

In Processors Templates inserted name_of_folder.name_of_file.custom_proc

Answer 1

Most likely you need a context processor .