How to pass the url of the page from which the request was sent to the hidden field of the form (ModelForm)?

Question

Django

Input data:
models

class User_information(models.Model):
    name = models.CharField(max_length=50)
    second_name = models.CharField(max_length=50)
    phone = PhoneNumberField()
    email = models.EmailField()
     url = models.SlugField()

forms

class PostForm(ModelForm):
    class Meta:
        model = User_information
        fields = ['name', 'second_name', 'phone', 'email', 'url']
        labels = {
            'name': _('Имя'),
            'second_name': _('Фамилия'),
            'phone': _('Телефон'),
            'email': _('EMAIL'),
        }
        widgets = {
            'name': Textarea(attrs={'cols': 80, 'rows': 3}),
           # 'url' : HiddenInput(), как добавить виджет скрытого поля
        }

Views

def detail(request, slug):
    html = 'post_detail.html'
    categories = Category.objects.all()
    query_set = get_object_or_404(Post, slug=slug)
    form = PostForm(request.POST or None)
    if form.is_valid():
        name = form.cleaned_data['name']
        second_name = form.cleaned_data['second_name']
        phone = form.cleaned_data['phone']
        email = form.cleaned_data['email']
        query_set = form.save(commit=False)
        query_set.save()
        # send_mail(name)
        form = PostForm()
        print(name, second_name, phone, email)
    context = {
        'detail': query_set,
        'categories': categories,
        "form": form,
    }
    return render(request, html, context)

How to auto-substitute in the hidden url field of the form page?
How to display the url of this page in the view?

Answer 1

<input name="url"  value="{{request.get_full_path}}">