How to pass Lable as function parameter (Tkinter Python3)?

Question

Python

There is a code that draws a window and a Label inside it. There is a function that simulates typing, you need the ability to pass the name of the label in which the animation should take place, but when you try to do this, it is passed as an int. How to fix it?
PS If inside the function with animation the name of the label is written not as a parameter, but simply as a global name, then everything works.
Non-working code with an attempt to pass a parameter:

import random
from tkinter import *


root = Tk()
root.title("Initial Fantasy")
root.geometry("800x600")

def typewrite(labelWidget,counter=1):
    labelWidget.config(text="Some Text"[:counter])
    root.after(random.randrange(30,150), lambda: typewrite(counter+1))

mainTextBox = Label(text="", fg="#eee", bg="#333")
mainTextBox.place(relx=.50, rely=.325, anchor="center")
typewrite(mainTextBox)

root.mainloop()

Error code:
AttributeError: 'int' object has no attribute 'config'
Working code where the animation is done, but without the ability to pass the desired label:

import random
from tkinter import *


root = Tk()
root.title("Initial Fantasy")
root.geometry("800x600")

def typewrite(counter=1):
    mainTextBox.config(text="Some Text"[:counter])
    root.after(random.randrange(30,150), lambda: typewrite(counter+1))

mainTextBox = Label(text="Этого текста быть не должно", fg="#eee", bg="#333")
mainTextBox.place(relx=.50, rely=.325, anchor="center")
typewrite()

root.mainloop()

Answer 1

In the first code example, label is not always passed. Fix it lambda: typewrite(counter+1)and lambda: typewrite(labelWidget, counter+1)everything should work.