How to pass get parameters to url in Django?

Question

Django

Hello everyone
I can't figure out how to pass get parameters to URl if they are not hardcoded.
Final URL
site.ru/coupons?category=1
urls.py
url(r'^coupons$', views.coupons, name='coupons'),
I'm trying to output something like this in html:

<a href="{% url "coupons" category=1 %}">Первая категория</a>

And doesn't work

Answer 1

Documentation