How to pass bash arguments to script and keep config formatting inside script?

Question

bash

Hello!
Guys, how do I want the script to receive arguments that it will substitute into variables inside the script
and how to save the formatting of the config so that it generates it already with the necessary parameters?
Example:
script.sh /patch/to/dst/folder 100M
Coffing itself
/var/log/messages {
rotate 5
weekly
postrotate
/usr/bin/killall -HUP syslogd
endscript
}
"/var/log/httpd/access.log" {
rotate 5
mail www [at] my.org
size 100M
sharedscripts
postrotate
/usr/bin/killall -HUP httpd
endscript
}
/var/log/news/* {
monthly
rotate 2
olddir /var/log/news/old
missingok
postrotate
kill -HUP `cat /var/run/inn.pid`
endscript
nocompress
}
~/log/*.log {}

Answer 1

Use the variables ${n}, where n is the ordinal number of the argument. For example, ${1} would contain the string "/patch/to/dst/folder".

Answer 2

https://stackoverflow.com/questions/2914220/bash-t...
https://github.com/wercker/step-bash-template
bash template