How to pass all parameters in BASH to an internal call?

Question

bash

Hello. The point is the following.
I have a file ./start.shthat conditionally serves to make it easier to run a longer command

/usr/local/lib/path/to/lib/bin /home/user/path/to/some/file

. So. There was a need to pass several parameters to the internal call.
I want all parameters during the call to be
./start.sh --max=100
transferred to the internal call

/usr/local/lib/path/to/lib/bin /home/user/path/to/some/file --max=100

How to implement the transfer of all parameters to an internal call?

Answer 1

Pass as "$*" or "[email protected]"

./start.sh
/usr/local/lib/path/to/lib/bin /home/user/path/to/some/file [email protected]

But in your case with a one-line command, it's easier to make an alias
and call:
STARTSH --max=100
The only thing is to put this alias in .profile or .bashrc so that it is available immediately upon login.
autocomplete works with aliases, so ST+tab is enough

Answer 2

internal call do this
/usr/local/lib/path/to/lib/bin /home/user/path/to/some/file $1
and you can set the parameter