How to pass a pointer to a function if it takes a reference?

Question

C++ / C#

hello i have a function

template <typename type>
  static void readMemory(uintptr_t offset, unsigned int length, type var) {
    ReadProcessMemory(targetHandle, (LPVOID)offset, &var, length * sizeof(type), 0);
  }

I call her

uintptr_t adr; readMemory<uintptr_t&>(0x183422, 1, adr);

But now I need to pass a pointer to ReadProcessMemory

wchar_t* str = new wchar_t[length]; readMemory<wchar_t*>(0x124322, length, str);

//This doesn't work because ReadProcessMemory gets a reference from a pointer, how can I fix the situation...

Answer 1

No way. Make your function accept a pointer:

template <typename type>
  static void readMemory(uintptr_t offset, unsigned int length, type* var) {
    ReadProcessMemory(targetHandle, (LPVOID)offset, var, length * sizeof(type), 0);
  }

uint8_t arr[100500];
readMemory<uint8_t>(0x00, 10, arr);