How to pass a function as an argument to bot.send_photo?

Question

Python

I am writing a bot in python. There is a function that gets pictures by class:

def getImages(limit): # картинки
    return soup.find_all('img', class_='market_listing_item_img', limit=limit)

And also there is a command that displays a picture (at the specified url) and text:

@dp.message_handler(commands=['see_products'])
async def process_seeproducts_command(message: types.Message):
    limit = 3 
    i = 0
    while i <= limit:
        prices = parser_from_tp.getPrices(limit)
        titles = parser_from_tp.getTitles(limit)
        quantities = parser_from_tp.getQuantities(limit)
        await bot.send_photo(chat_id, url, caption='Товар: '+titles[i].text+'\nЦена: '+prices[i].text+'\nКол-во: '+quantities[i].text)
        i = i+1

I need to pass a function to bot.send_photo as an argument, not a url, how can I do this?

Answer 1

Firstly, then the function needs to be improved, because it returns bs4 objects, not
urls. Secondly, sendPhoto sends one image. So either return just one url or use sendMediaGroup