How to pass a dictionary name to a function?

Question

Python

Good afternoon. There was a problem with kwargs in Python, I searched the Internet, but did not find the answer. When calling the function, python gives an error that it expects 0 arguments, and 1 is passed. If I pass the dictionary itself instead of the name of the dictionary, then there are no errors, but I would like to pass exactly the name of the dictionary. Explain what is wrong. Thanks in advance :)

people = {
  'josh': 'man',
  'jack': 'man',
  'anna': 'woman'
}

def people(**kwargs):
  for name, sex in kwargs.items():
    print(name + ' is a ' + sex)

people(people)

Answer 1

people(**people)

Answer 2

how are these arrays related?

Answer 3

and the standard <?print_r($array)?> doesn't work?