How to make the script take the last minute of the record from the file?

Question

bash

Please tell me how to set a parameter in the script so that it takes the last minute, for example
#!/bin/bash
for ii in $(journalctl -p err > erors.txt)
do
sleep
done
-- Logs begin at Mon 2018-03-05 13:09:15 EST, end at Mon 2018-03-05 14:30:34 EST
Mar 05 13:09:34 localhost.localdomain systemd[1]: Failed to start logs in /restar
Mar 05 13:18:07 localhost.localdomain systemd[1]: Failed to start logs in /restar
Mar 05 13:20:28 localhost.localdomain kernel: e1000 0000:00:03.0 enp0s3: Reset a
Mar 05 13:26:17 localhost.localdomain systemd[1 ]: Failed to start logs in /restar
Mar 05 14:08:05 localhost.localdomain systemd[1]: Failed to start logs in /restar
for example, the script was launched at 14:09:00, it should output only the last record to the file =) #(I don’t know how to describe it in another way)

Answer 1

last entry from the file:
but maybe you just want the last entry from the log, then like this:
journalctl -p err -n 1